Question

A sum when reckoned at 6% per annum simple interest amount to RS.4130 in 3 years . Find the sum plzz help me first plz plzz plz ​

Answer 1

Answer:

4130/9 is the answer। hopit helps.

Answer 2

To Find :-

The Sum of Money of the Principal.

Given :-

• Amount = ₹ 4130

• Time = 3 years

• Rate of interest = 6 % p.a.

We Know :-

SimPle Interest :

$\blue{\bf{\boxed{SI = \dfrac{P \times R \times t}{100}}}}$

Where :-

• SI = Simple Interest

• P = Principal

• R = Rate of interest

• t = Time period

Concept :-

Let the Principal be P and Simple Interest be I.

We know that ,

→ A = P + SI

Substituting the value of Amount and the taken Variable for the principal (i.e P) , we get :

→ ₹ 4130 = P + I

→ ₹ 4130 - P = I

→ l = ₹ 4130 - P

Hence ,

• The Principal is ₹ P , and

• Simple Interest is ₹ (4130 - P).

Solution :-

We Know :

• Principal = P

• Simple Interest = (4130 - P)

• Rate of interest = 6 % p.a.

• Time Period = 3 years.

Using the formula for simple Interest , and by substituting the values in it , we get :

$\implies \bf{SI = \dfrac{P \times R \times t}{100}} \\ \\ \\ \implies \bf{(4130 - P) = \dfrac{P \times 6 \times 3}{100}} \\ \\ \\ \implies \bf{(4130 - P) = \dfrac{P \times 18}{100}} \\ \\ \\ \implies \bf{(4130 - P) \times 100 = P \times 18} \\ \\ \\ \implies \bf{413000 - 100P = 18P} \\ \\ \\ \implies \bf{413000 = 100P + 18P} \\ \\ \\ \implies \bf{413000 = 118P} \\ \\ \\ \implies \bf{\dfrac{413000}{118} = P} \\ \\ \\ \implies \bf{3500 = P} \\ \\ \\ \implies \purple{\bf{P = 3500}}$

Hence, the sum of money or the Principal is ₹ 3500.