Question

A sum when reckoned at 6% per annum simple interest amount to rupees 4130 in 3 years. Find the sum.

Answer 1

When solving this question,
Consider the sum reckoned be ₹ P.

Amount = ₹ 4130

Rate% = 6% p.a.

Time, t = 3 years

Amount = PRT/100 + P

4130 = (P * 6 * 3)/100 + P

4130 = 18 P/100 - P

4130 = 118 P/100

P = 4130*100/118

P = ₹ 3500

The required sum = P = ₹ 3500

Answer 2

Your Answer
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Given,

Amount = ₹ 4130

Rate = 6 % per annum

Time = 3 years

Let the sum be ₹ P.

Now,

We know that

$Amount \: \: = \: \: P + SI \\ \\ = > 4130 = P + ( \frac{P \times R \times T}{100} ) \\ \\ = > 4130 = P + ( \frac{P \times 6 \times 3}{100} ) \\ \\ = > 4130 = P + \frac{9P}{50}$

$= > 4130 = \frac{50P + 9P}{50} \\ \\ = > 4130 = \frac{59P}{50}$

$= > 59P = 4130 \times 50 \\ \\ = > P = \frac{4130 \times 50}{59}$

$= > P = Rs\:\: 3500 \\ \\ Hence, \: \: the \: \: sum \: \: is \: \: Rs \: \: 3500$

$I \: \: hope \: \: it \: \: will \: help \: \: you$