A supply of 24V is applied across a resistance combination consisting of the
following: three resistors of 6Ω, 12Ω and 36Ω connected in parallel and a fourth
resistor of 16.4Ω connected in series with the parallel group. Calculate: [ ]
a) Total current
b) Voltage across the parallel group
c) The current flowing through each resistor in the parallel group
Answers
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Answer:
a) 1.2 b) 24 c) 4, 2 , 0.6
Explanation:
resultant resistance across parallel group is 1/R=1/6+1/24+1/36
1/R=10/36
b) R=3.6ohm
now, a) V=IR
I=V/R
I=24/20=1.2A
c) I= 24/6=4A
I=24/12=2A
I=24/36=0.6A
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