Question

A surface with measures 80cm x 48 cm x 24 cm is to be covered with a Tarpaulin cloth. How
many metres of tarpaulin ofwidth 96 cm is required to cover 100 such suitcases?​

Answer 1

ANSWER:-

144

EXPLANATION:-

Given ⇒

l=48cm,b=80cm,h=24cm

total surface area of suitcase =2(lb+bh+hl)

=2[(48)(80)+(80)(24)+(48)(24)]

=13824cm^2

⟹ Area of 100 suitcases =100×13824cm^2

Area of rectangle tarpaulin =lb

Meters for tarpaulin =

96

13824×100

=14400 cm =144 m

Answer 2

⇒ Given :-

• A suitcase with measures 80 cm x 48 cm x 24 cm is to be covered with a Tarpaulin cloth.

⇒ To Find :-

• How  many metres of tarpaulin of width 96 cm is required to cover 100 such suitcases?​

⇒ Solution :-

• Let length = l, breath = b and height = h

• Length of the suitcase = 80 cm

• Breath of the suitcase = 48 cm

• Height of the suitcase = 24 cm

• Total surface area of 1 suitcase

= 2( lb + bh + hl ) cm²

= 2( l x b + b x h + h x l ) cm²

= 2( 80 x 48 + 48 x 24 + 24 x 80 ) cm²

= 2( 3840 + 1152 + 1920 ) cm²

= 2 x 6912 cm²

= 13824 cm²

• Area of tarpaulin = 100 x Area of 1 suitcase

                                     = 96 x l = 100 x 13824

• ∴ Length = 100 x 13824 ÷ 96

                        = 14400 cm

                        = 14400 x 1 ÷ 100 m

                        = 144 m

Ans. 144 m of cloth is required to cover 100 suitcase.

$\huge{\boxed{\sf{\ Hence\:\:Proved}}}$