Question

A survey of cars owned by 200 families in a society shows the following results: (3)
Number of cars 0 1 2 3 or more
Number of families 20 105 60 15
Out of these families, one is chosen at random. What is the probability that
the chosen family has (a) 1 car (b) 3 or more cars (c) no car

Answer 1

a). 1 car = 21/40

b). 3 or more cars = 3/40

c). no car = 1/10

Step-by-step explanation:

As we know,

Probability = No. of favorable outcomes/Total no. of outcomes

a). 1 Car

P(2 cars) = No. of favorable outcomes/Total no. of outcomes

= 105/200

= 21/40

b). 3 or more cars

P(3 or more cars) = No. of favorable outcomes/Total no. of outcomes

= 15/200

= 3/40

c).  No car

P(No cars) = No. of favorable outcomes/Total no. of outcomes

= 20/200

= 1/10

Learn more: Probability

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