Question

A survey was conducted among 200 magazine subscribers of three different magazines A, B

and C. It was found that 75 members do not subscribe magazine A, 100 members do not

subscribe magazine B, 50 members do not subscribe magazine C and 125 subscribe atleast

two of the three magazines. Find (i) Number of members who subscribe exactly two

magazines. (ii) Number of members who subscribe only one magazine.​

Answer 1

Answer:

Total number of persons=100

Number of persons who read magazine A=n(A)=28

Number of persons who read magazine B=n(B)=30

Number of persons who read magazine C=n(C)=42

Number of people who read both  magazine A and B = n(A∩B)=8

Number of people who read both  magazine B and C= n(B∩C)=5

Number of people who read both  magazine A and C = n(A∩B)=10

Number of people who read both  magazine A, B and C = n(A∩B∩C)=3

Number of people who read none of the three magazines= n(A∪B∪C)=n(A)+n(B)+n(C)−n(A∩B)−n(B∩C)−n(C∩A)+n(A∩B∩C)

n(A∪B∪C)=28+30+42−8−5−10+3

Therefore total number of readers=80

Number of readers who read none of the three magazines= 100−80=20

Answered By

Step-by-step explanation: