Question

A surveyor wants to find out the height of a tower. He measures ∠A as tan A=

. What
is the height of the tower if A is 40 m from its base as shown in the figure?

Answer 1

Given Data :-

• Height of Tower = ∠A = Tan A
• A = 40m

To Find :- Height of Tower

Solution :-

if ∠A = 40°

Then ,

$\huge \sf \frac{adj}{opp} = tan \: \: a$

$\huge \sf \boxed{ \sf tan \: \: 40 \degree \: = 0.83}$

now substitute values , we get

$\huge \sf tan \: \: 40 \degree = \frac{40}{opp}$

$\large \sf opposite (opp) \: \: = \frac{40}{0.83} = 48.19$

$\large\therefore \sf \: Height \: \: of \: \: tower \: \: = \: 48.19 \: \: mtrs$

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