Question

A sweetseller has 420 kaju barfis and 130 badam baris and 130 badam barfis. She wants to stack them
in such a way that each stack has the same number of barfis and they take up the least area of the tray. What is the number of barfis that can be placed in each
stack for this purpose ?​

Answer 1

Answer:

In order to do this (i.e making stacks) ,she must find the hcf (420 , 130 ) .

So the hcf by Euclid Division Lemma process is as follows:

Step-by-step explanation:

420= 130×3 + 30

130= 30×4 + 10

30= 10×3 + 0

Since, the remainder is 0 at last step so 10 is the hcf.

So the sweetseller must make 10 stacks for completing her purpose.

Answer 2

$\large \bigstar{\underline{\green{\mathfrak Answer:}}}$

The sweetseller can make stacks of 10 for both kinds of burfis to cover the least area of the stack

$\bold{\underline {Given:}}$

A sweet seller has 420 kaju barfies and 130 badam barfies she wants to stack them in such a way that each stack has the same number.

$\bold{\underline {To\:Find :}}$

The least area of the tray what is the number that can be placed in each stack for this purpose =?

$\large \bf{\underline{\underline{Step\: by\: step \:explanation:}}}$

Area of the tray will be least if the sweetseller stacks the maximum number of burfis in each stack.

Since each stack has the same number of burfis, therefore, the number of stack will be least if the number of burfis in each stack is equal to HCF of 420 and 130.

To find HCF of 420 and 130, we apply the Euclid's division lemma to 420 and 130.

We have

420 = 130 x 3 + 30

130 = 30 x 4 + 10

30 = 10 x 3 + 0

So, HCF of 420 and 130 is 10.

Therefore, the sweetseller can make stacks of 10 for both kinds of burfis to cover the least area of the stack