A swimmer crosses a flowing stream of width 'w' to and fro in time t1. The time taken to cross the same distance up and down the stream in t2. If t3 is the time the swimmer would take to swim a distance 2w in still water. Then
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The time taken to cover the same distance up & down the stream is t2 . if t3 is the time swimmer would take to swim a distance 2ω in still ...
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given =
- time = t1
- time taken to cross the same distance up and down the stream in t2.
- t3 is the time the swimmer would take to swim a distance 2w in still water
- width =W
- distance = 2W
to find = t1
solution =
here v will be the velocity and u is the velocityof swimmer,
apply the formula,
t1 = 2 ( W / √u²-v²)
t2 = W / u+V + W/ u-v = 2uW/ u²-v²
t3 = 2W/u
so we can conclude that t1² = t2t3
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