Question

If cos. A=5/13 and sin=4/5, find the value of sin(A-B)
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Answer 1

Answer:

sin(A-B) = sinA cosB - cos A sin B

Answer 2

Answer:

cosA= 5/13 cosB=3/5

sinA= 12/13 sin B= 4/5

sin(A − B) = sinA cosB − cosA sinB

sin(A − B) = 5/13 ×3/5 - 5/13×4/5

sin(A − B) = 36/65 - 4/13

sin(A − B) = 36-20/13

sin(A − B) =16/13