A swimmer makes his strokes perpendicular to the flow of river at speed 8 metre per second relative to still water. he arrives at a point 20 metre downstream from the point directly across the river which is 40 metre wide. the velocity of the swimmer with respect to ground will be
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The velocity of the swimmer with respect to ground is Vm = 4 √ 5 m/s.
Explanation:
Speed of swimmer = 8 m/s
VR = Horizontal component of velocity ( Velocity of swimmer with respect to ground)
Vm = slope of the velocity
t = 40 / 8 = 5 m/s
VR = 0 / 5 = 4 m/s
V(m) = vmR + vR
|V(m)|^2 = (8)^2 + (4)^2
|V(m)|^2 = 64 + 16
|V(m)|^2 = 80
Taking square root on both sides.
Vm = 4 √ 5 m/s
Hence the velocity of the swimmer with respect to ground is Vm = 4 √ 5 m/s.
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