Question

a swimmer wants to cross a 200m wide river moving with velocity 2m/s.velocity of the swimmer w.r.t. the river is 1m/s.how far will he go to reach the opposite bank?

Answer 1

$\large\underline{\underline{\sf Given:}}$

• Width of river (W) = 200m

• Velocity of river $\sf{(V_r)}$=2m/s

• Velocity of swimmer $\sf{(V_s)}$ = 1m/s

$\large\underline{\underline{\sf To\:Find:}}$

• How far will he go to reach the opposite bank or drift (d) = ?

$\large\underline{\underline{\sf Solution:}}$

We know ,

$\large{\boxed{\sf \frac{W}{V_m}=\frac{Drift(d)}{V_r}}}$

$\large\implies{\sf \frac{200}{1}=\frac{d}{2} }$

$\large\implies{\sf d=400m }$

$\large\red{\boxed{\sf Drift (d)=400m }}$

OR

$\large\implies{\sf tan \theta=\frac{2}{1}}$

$\large\implies{\sf tan \theta=\frac{d}{200} }$

$\large\implies{\sf \frac{2}{1}=\frac{d}{200}}$

$\large\implies{\sf d=400m}$

$\large\red{\boxed{\sf Drift(d)=400m}}$

$\Large\underline{\underline{\sf Answer:}}$

•°•

$\underline{\underline{\sf 400m\:far\:he\:will\:go\:to\:reach\:the }}$

$\underline{\underline{\sf opposite\:bank}}$

Answer 2

Answer:plzz go through the line by line explanation

Explanation: