Question

a swimming pool is 20 m in length 15 m in breadth, 4 m in depth find the cost of cementing its floor and walls at 35 per metre square

Answer 1

HEY BUDDY..!!

HERE'S THE ANSWER..

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♠️ It is logical question with mensuration ,

▶️ It is clear that we have to cement only 5 sides , 4 lateral sides and from bottom.. Using this concept our formula become

✔️ Area to be cemented = Total surface area - area of top .

=> Area to be cemented = 2 [ ( L × B ) + ( B × H ) + ( H × L ) ] - [ L × B ]

⏺️L ( length ) = 20 m

⏺️B ( breadth ) = 15 m

⏺️H ( depth or height ) = 4 m

⏺️ Now putting values in formula...

=> Area to be cemented = 2 [ ( 20 × 15 ) + ( 15 × 4 ) + ( 4 × 20 ) ] - [ 20 × 15 ]

=> Area to be cemented = 2 [ ( 300 ) + ( 60 ) + ( 80 ) ] - [ 300 ]

=> Area to be cemented = 2 [ 440 ] - [ 300 ]

=> Area to be cemented = 880 - 300

=> [ Area to be cemented = 580 m^2 ]✔️

▶️ Now cost of cementing is ₹ 35 per metre square , So cost of cementing 560 m^2

=> Cost = 580 × 35

=> [ Cost = ₹ 20,300 ] ✔️✔️

▶️ Cost of cementing will be ₹ 20,300

HOPE HELPED ..

JAI HIND..

:-)

Answer 2

$\bf \large \it{Hey \: User!!!}$

given :-

>> length of the swimming pool = 20m
>> breadth of the swimming pool = 15m
>> height (depth) of the swimming pool = 4m

According to the question, we have to find the cost if cementing it's floor and walls at rs 35 per m² so first we have to find the area to be cemented.

as it's mentioned that we have to find the cost of cementing it's floor and walls, so we will use CSA + 1 base formula.

CSA = curved surface area (four walls)

1 base = base ( floor of the swimming pool )

CSA + 1 base of the swimming pool = 2h ( l + b ) + lb
= 2 × 4 ( 20 + 15 ) + ( 20 × 15 )
= 8 ( 35 ) + 300
= 280 + 300
= 580m²

hence, cost of cementing at rs 35 per m² = 35 × 580 = rs 20300

$\bf \large \it{Cheers!!!}$