A swimming pool is 21 m long, 14 m wide, and 6 m deep. Find the sum of the area of the four walls and is floor?
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Answered by
2
Answer: apply the basic formula that is
2H(L+B) + LB
TAKE L,B,H from question and solve that .
Or
Apply formula of total surface area pf cuboid 2(lb+bh+lh) and subtract lb from it
Answered by
12
Answer:
l = 21m b = 14m h = 6m
Total area = 2(lb+bh+lh)
= 2(294+84+126)
= 2(504) = 1008m²
Area of four walls and the floor = 1008 - 294 = 714m²
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