Question

A swimming pool is 260m long and 140m wide.,,If 54600${m}^{3}$ of water can Be Stored so Then what would be its height (Swimming Pool)

Answer 1

The pool is in the form of cuboid
$volume = length \times breadth \times height \\ 54600 = 260 \times 140 \times h \\ h = \frac{54600 \: {m}^{3} }{260 \: m \times 140 \: m} \\ h = \frac{546 \: {m}^{3} }{26 \times 14 \: {m}^{2} } \\ h = \frac{42 \: {m}^{3} }{2 \times 14 \: {m}^{2} } \\ h = \frac{3}{2} m\: or \: 1.5 \: m$

Answer 2

$\underline{\textbf{Hey Mate Here Is Your Answer }}$

$\underline{\textbf{Given That.. }}$

A Swimming Pool is 260m Long And 140m Wide And Now It's Also Said That It Can Store 54600${m}^{3}$Of Water And Now We Need To Find It's Height.

So Now Let's Move For Solution ..

$\underline{\textbf{Solution}}$

Now According To Question ...

$\mathbf{Length \:(L)\: =\: 260m}$

$\mathbf{Breadth \:(B)\: =\: 140m}$

Now In Question It's Said That It Can Store Water upto 54600 ${m}^{3}$

So We Have..

$\mathbf{Volume \:(V)\: =\: 54600{m}^{3}}$

Now We Know That Volume Of A Cuboid $\bold{\longrightarrow}$

$\boxed{\mathbf{Volume \:(v)\:=\: Length\: \times\: Breadth \:\times \:Height}}$

Now By Putting Values Of Volume = 54600(m)^3 , Length = 260m And Breadth = 140m We Have..

$\mathbf{54600 {m}^{3} = 260m \times 140m \times height} \:$

Now Finding Product Of RHS We Have..

$\mathbf {54600 {m}^{3} = 36400 {m}^{2} \times height}$

So Now Taking 36400 RHS To LHS We Have...

$\mathbf { \frac{54600 {m}^{3} }{36400 {m}^{2}} = height}$

So Now We Have ...

$\boxed{ \mathbf{Height \: = 1.5m }}$

Hence The Required Answer Is ...

$\boxed{\boxed{\boxed{\mathbf{Height\:= 1.5m}}}}$

$\Large{\textsf{Thanks..}}$