Physics, asked by gsoqbdhiwbdmsjdb, 1 month ago

A swimming pool of width 9.0 m and length 24.0 m is filled with water to a depth of 3.0 m. Calculate pressure on the bottom of the pool due to the water.​

Answers

Answered by shobhadevi66744
0

Answer:

30000Pa

Explanation:

H=3m

Rho=1000kg/m^3

G=10m/s^2

So,

Pressure=h×rho×g

=3×1000×10

=30000Pa

Answered by anushkaprasad019
5

Explanation:

first we need to find mass of water to find force:-

density = mass / volume

mass = density × volume

mass = density × ( length ×breadth × height)

( density of water is always be 1000kg/m3)

so , Mass = 1000kg/m3× ( 24.0×9.0×3.0)

mass = 1000kg/m3× 648m3

Mass = 6,48,000

Now, force = 6,48,000x 10

= 64,80,000N

According to question

area of swimming pool= length x breadth

so , 24.0x 9.0

= 216 m2

pressure = force / area

pressure = 64,80,000/ 216m2

p = 30,000 PA

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