A symmetrical convergent lens is having focal length equal to twice the radius of curvature of its surface then refractive index of material of lens is equal to
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Answer:
Given:f=R
1
=−R
2
=R(let)
from lens maker's formula
f
1
=(μ−1)(
R
1
1
−
R
2
1
)
R
1
=(μ−1)
R
2
μ=
2
3
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