Question

a system absorbs 85.5 j heat energy from the environment and it’s internal energy increase by 45.7 j find the work done by the system on the environment?​

Answer 1

Explanation:

q=50 kJ (as heat is absorbed, so it is positive)

w=−20 kJ (as work is done by the system, so it is negative)

∴ΔU=q+w=50−20=30kJ

Therefore, internal energy change increases by 30 kJ.