Science, asked by aliyakhanam7024, 19 days ago

A system has 50 Pascal of osmotic pressure and its turgor pressure is 0.Now due to entry of some water osmotic pressure decreases by 10 Pascal then what will be the change in DPD of system is

Answers

Answered by prathishta22p
2

Answer:

Explanation:

Water moves from an area of lower diffusion pressure deficit (DPD) to an area of higher DPD. The value of DPD is calculated as the algebraic difference between osmotic pressure and turgor pressure. In a flaccid cell, the turgor pressure is zero and hence DPD will be equal to the osmotic pressure. As water enters a cell, there is an increase in turgor pressure, as the solution in cell sap turns less concentrated there is a fall in osmotic pressure and consequently the DPD falls. In a fully turgid cell, the value of DPD is equal to zero and turgor pressure is numerically equal to osmotic pressure.

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