Question

A system has two charges qA = 2.5 × 10–7 C and qB = –2.5 × 10–7 C located at points A: (0, 0, –15 cm) and B: (0, 0, +15 cm), respectively. What are the total charge and electric dipole moment of the system?

Answer 1

Total charge of electric dipole = zero coulomb

Magnitude of Dipole moment,

|p| = (Magnitude of either charge) × (Distance between 2 charges) = q.2a

Given, 2a = 30 cm, q = 2.5 × 10‒7 C

= (2.5 × 10‒7) × (30)

= 7.5 × 10‒8 C-m

Answer 2

Hello friends.

Solution:-

given by:-

》At A, amount of charge, qA = 2.5 × 10−7C

》At B, amount of charge, qB = −2.5 × 10−7 C

》Total charge of the system,

》q = qA + qB = 2.5 × 10-7 C − 2.5 × 10−7 C = 0

》Distance between two charges at points A and B,

》d = 15 + 15 = 30 cm = 0.3 m

》Electric dipole moment of the system is given by,

》p = qA × d = qB × d = 2.5 × 10−7 × 0.3 = 7.5 × 10−8 C m along positive z-axis

》Therefore, the electric dipole moment of the system is 7.5 × 10−8 C m along positive

hope it's helpful for you...