A system releases 125 kJ of heat while 104 kJ of work is done on the system.
Calculate the change in internal energy.
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Answer:
The first law of thermodynamics is given as ΔU = Q − W,
ΔU= change in internal energy of a system
Q - Net Heat Added to System
Q = +ve if net heat transfer to
system
Q = - ve if net heat transfer out of system
W is Net work done by the system
W = + ve if done by system
W is - ve if done on system ,
ΔU= Q - W
A system releases 125 kJ of heat
Means out of systemQ = - 125 KJ
work is done on the system hence - ve
=> W = -104 KJ
ΔU= - 125 - (-104)=> ΔU= - 21 KJ
change in internal energy of system = Decrease of 21 KJ
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