Question

A table clock has its minute hand 4.5cm long. Find the average velocity of the tip of the minute hand (a) between 12:00 a.m to 12:30 a.m and (b) between 12;00 a.m to 12;30 p.m

Answer 1

Speed of hour hand=0.5 degrees per minute.
Speed of minutes hand=6 degrees per minute
angular distance moved by the minute hand between

12.00Am o 12.30 Am=30 (6 degrees ) =180 degrees
average angular velocity in this period is
π/1800 rad/s
so, angular velocity of the tip of minute hand will be
4.5 x π/1800
=0.0025πcm/s
similarly for the second part the minute hand will cover( 6

degrees)(750)=4500 degrees
Angular velocity in this period is
25π/750x60=π/1800 rad/s
Average velocity of the tip of minute hand will be
4.5 x π/1800=0.0025πcm/s

Answer 2

Answer:

5 x 10 raise to - 3 cm/s

Explanation:

see the picture for better understanding