Question

A table contains the ordered pairs (3, 42.25) and (5, 50.75). If the relationship in the table is linear, explain how to find the initial value.

Answer 1

Answer:

35.5

Step-by-step explanation:

Because there is no table to be able to see what are first values of "x" and "y" in the table, then the initial value of a linear function is the value of y of f(x), when the value of x is 0.

First we have to write a linear equation for the line which contain given points.

m = $\frac{50.75-42.25}{5-3}$ = $\frac{4.5}{2}$ = $\frac{9}{4}$

($y_{2}$ - $y_{1}$) = m ($x_{2}$ - $x_{1}$)

y - 42.25 = $\frac{9}{4}$ (x - 3)

y = $\frac{9}{4}$ x - $\frac{27}{4}$ + 42.25

y = $\frac{9}{4}$ x + 35.5

If x = 0 , y = 35.5

Answer 2

Answer:

Because there is no table to be able to see what are first values of "x" and "y" in the table, then the initial value of a linear function is the value of y of f(x), when the value of x is 0.

First we have to write a linear equation for the line which contain given points.

Step-by-step explanation: