A table is pushed 15 m across a room with the force of 50 N.
What is the work done?
Answers
Explanation:
workdone=force×displacement ×cos theta
W=50×15×cos0°
W=750 j
Answer:
Diagram A Answer:
W = (100 N) * (5 m)* cos(0 degrees) = 500 J
The force and the displacement are given in the problem statement. It is said (or shown or implied) that the force and the displacement are both rightward. Since F and d are in the same direction,the angle is 0 degrees.
Diagram B Answer:
W = (100 N) * (5 m) * cos(30 degrees) = 433 J
The force and the displacement are given in theproblem statement. It is said that the displacement is rightward. It is shown that the force is 30 degrees above the horizontal. Thus, the angle between F and d is 30 degrees.
Diagram C Answer:
W = (147 N) * (5 m) * cos(0 degrees) = 735 J
The displacement is given in the problem statement. The applied force must be 147 N since the 15-kg mass (Fgrav=147 N) is lifted at constant speed. Since F and d are in the same direction, the angle is 0 degrees.