A takes 1 hr more than b in walking 24 km if a increase his speed by 50% he wiol take 1 hr less than b find the walking speed of a and b
Answers
Answer:
Distance = 24 km
Let’s assume,
Speed of A be “x” km/hr
Speed of B be “y” km/hr
We know,
Time = Distance/Speed
Step 1:
It is given that A takes 1 hr more than B
So,
Time taken by A = 24/x hr
Time taken by B = 24/y hr
∴ 24/x – 24/y = 1
⇒ 24/y = 24/x - 1 ….. (i)
Step 2:
Also, given that A increases his speed by 50% i.e., his speed now becomes “1.5 x” km/hr and thus takes 1 hr less than B.
So,
Time taken by A = 24 / (1.5 x) hr = 16/x hr
Time taken by B = 24/y hr
∴ 24/y – 16/x = 1
Substituting (i), we get
⇒ 24/x – 1 - 16/x = 1
⇒ 8/x = 2
⇒ x = 8/2 = 4 km /hr
And,
Substituting the value of x in eq. (i)
24/y = 24/4 – 1
⇒ 24/y = 5
⇒ y = 24 / 5 = 4.8 km /hr
Thus, the speed of A is 4 km/hr and B is 4.8 km/hr.
Answer:
speed of A = 4 km/hr
speed of B = 4.8 km/hr
Explanation:
Given the total Distance = 24 km
Let’s assume that;
Speed of A be “x” km/hr;
&
Speed of B be “y” km/hr
Since we know that;
Time = Distance/Speed
Since according to question it is being mentioned that;
A takes 1 hr more than B
So,
Time taken by A will be = 24/x hr
Time taken by B will be = 24/y hr
∴ 24/x – 24/y = 1..........(1)
Since according to question it is being mentioned that;
if A increase his speed by 50% he will take 1 hr less than B
A takes 1 hr less than B
Also, given that A increases his speed by 50% i.e., his speed now becomes “1.5 x” km/hr and thus takes 1 hr less than B.
So,
Now speed of A will increse by 50%
∴ 50 % off x = x + x/2 = 1.5x
Time taken by A will be = 24/1.5 hr = 16 /x hr
Time taken by B will be = 24/y hr
∴ 24/y - 16/x = 1..............(2)
Adding (1) and (2);
We get,
x = 4 km/hr
∴ The speed of A is 4 km/hr.
Putting x in eq (1);
y = 4.8 km/hr
∴ The speed of B is 4.8 km/hr.