A takes 10 days lessbthan the time taken by B to finish a piece of work. If both A and B together finish the work in 12 days, find the time taken by B to finish the work
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Answer:
30 days
Explanation:
Total no of days = 12 days
Let time taken by A to complete the work = x days
Let time taken by B to complete the work = (x+10) days
∴ In 1 day, A completes = 1 / (x) th work
∴ In 1 day , B completes = 1/ (x+10) th work
ATQ
1 / x + 1 / x+10 = 1/12
x+ x+10 / x2 + 10x = 1/12
12 (2x+ 10) = x2 +10x
24x + 120 = x2 + 10x
∴ x2 - 14x - 120 = 0
x2 - 20x + 6x -120 = 0
x( x-20) +6(x-20) = 0
∴ x= -6 or x= 20
But since x is no of days, x ≠ -6..
Hence, x = 20
⇒ A will take 20 days to finish the work while B will take (20 + 10)= 30 days to finish the work..
Hope this helps you..!!
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