A takes 4 hours, B 5 hours and C 6 hours to complete a task. How long will it take A and B to do as much work as C does in 4.25 hours?
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Step-by-step explanation:
Let A and B together complete the work in "t" hours
Now, according to question
Work done by A
t + [(1/A) + (1/B)] + 4.5 = (t + 4.5)/A
t/A = 4.5/B
A/B = t/4.5 ----(1)
Similarly work done by B,
t + [(1/A) + (1/B)] + 8 = (t + 8)/B
t/B = 8/A
A/B = 8/t ----(2)
Comparing (1) and (2), we get
t/4.5 = 8/t
t2 = 36
∴ t = 6 hours
∴ A and B will together complete the task in 6 hours
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