A takes 40 minutes to do a job . B Tajes 1 hour to do same job . A, B and C start doing that job togather. they complete it in only 15 minutes. Had C been alone how much time would he have taken to do that job
Answers
Answered by
0
Answer:
Let 1/A = 1/40
and 1/B = 1/60
and 1/A + 1/B + 1/C = 1/15
Add equation 1 and 2
1/A + 1/B = 5 / 120 = 1 /24
Subtract it from equation 3
1/C = 1/24 - 1 /15 = 1 / 40
C = 40 minutes
Similar questions