A takes 6 days less than B to finish a piece of work. if both A and B together can finish to work in 4 days. find the time taken by B to Finish the work
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a+ b 1 day work = 1/4
a 1 day work = 1/(x-6)
b 1 day work = 1/x
1/x + 1/(x-6) =1/4
x-6 +x /x^2 -12 =1/4
8x -24 = x^2 -12
x^2 -8x +12 =0
x^2 -6x-2x+12=0
x(x-6) -2(x-6) =0
(x-2)(x-6)=0
x=2 ,6
a 1 day work = 1/(x-6)
b 1 day work = 1/x
1/x + 1/(x-6) =1/4
x-6 +x /x^2 -12 =1/4
8x -24 = x^2 -12
x^2 -8x +12 =0
x^2 -6x-2x+12=0
x(x-6) -2(x-6) =0
(x-2)(x-6)=0
x=2 ,6
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