A takes 6 days less than time taken by B to finish the piece of work. if both A and B together can finish the work in 4 days Find the time taken by B to finish the work
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no. of days taken by A to finish that work = x
then, no. of days taken by B to finish that work = x+6
now, work done by A in one day = 1/x and work done by B in one day = 1/x+6
now, work done by both A and B in one day,
1/x + 1/x+6 = 1/4
{(x+6)+x}/x(x+6) = 1/4
8x + 24 = x2 + 6x
x2-2x - 24 = 0
x2 -6x +4x -24 = 0
x(x-6) +4(x-6) = 0
(x+4) (x-6) = 0
so, x= 6 (neglecting x = -4)
so, time taken by B to finish the work = x+6 = 12 days
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