Question

A takes 8 days more than'b' to complete a certain work.If both of them together can complete 90% of the work in 16 days.then find the time taken by 'B' to complete the whole work alone??​

Answer 1

Answer:

Let the time taken by B working alone = x days,

So, time taken by A working alone = (x + 8) days

∵ A complete 75% of the work,

So, the day he will work = 75% of (x+8) = 75(x+8)/100=3(x+8)/4

B has to complete 25% of work,

That is, days he will work = 25% of x = x/4

Since, B leaves the work 9 days before the work is finished,

Days for which A worked - Days for which B worked = 9 days.

3 (x+8)/4 - x/4 = 9

(2x + 24) / 4 = 9

2x = 24

X = 6

Now, x + 8 = 6 + 8 = 14

Hence, time taken by A to finish the work alone would be 14 days.