Math, asked by abdulsumear8612, 1 year ago

A takes twice as much time as b or thrice as much time as c to finish a piece of work. Working together, they can finish the work in 2 days. B can do the work alone in:

Answers

Answered by ImSkyeTheDarkWarrior
25

Answer:

B can do it alone for 6 days. and C can do it alone in 4 days.

Step-by-step explanation:

From the question we can see that B is twice efficient than A and C is thrice efficient than A

If, A does 1 unit of work per day, B will do 2 units and similarly C will be doing 3 units

Now, A+B+C one day work=6 units

Since they complete the work in 2 days, so total work will be 2×6=12 units

B alone will take 12/2 days = 6 days

C alone will take 12/3 = 4 days

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