Biology, asked by GautamPrabhu, 1 year ago

a tall pea plant bearing violet flowers is crossed with short pea plant bearing white flowers workout the F1 and F2 generation and give the phenotypic ratio.

Answers

Answered by aqibshaikh
45
it's a Mendel's dihybrid experiment where two characters are considering at one time.

here we have tall plant with violet flowers and short plant with white flowers.

TALL character denoted by T
short character as t
PURPLE character as P
white character as p

1) TTPP. cross ttpp

Result TtPp. (F1 generation)

then self pollination of F1 generation



phenotypic ratio will be 9:3:3:1.

the 9 represents the proportion of individuals displaying both dominant traits

the first 3 represents the individuals displaying the first dominant trait and the second recessive trait

the second 3 represents those displaying the first recessive trait and second dominant trait

the 1 represents the homozygous, displaying both recessive traits.

hope you understand

GautamPrabhu: is there a destined variable for every trait like u said its P and p for violet and white respectively
aqibshaikh: we are considering colour character.
aqibshaikh: purple as a dominant and white as a recessive.
aqibshaikh: thats why denoted P capital for purple and small p is for white
GautamPrabhu: so can we use any alphabet or does it have to be P and p only
aqibshaikh: no...its better to use dominant character's first alphabet is best.. otherwise u will be confused
aqibshaikh: hope u got it
GautamPrabhu: thanks a lot
Answered by yuvaganeshk
22
Tall plant, violet flowers: TTVV
Short plant, white flowers: ttvv
hence, by performing a cross between them, we get
                        TtVv  (F1 generation)
By self crossing F1 generation,(TtVv    X     TtVv), we get 
phenotypic ratio     9(tall violet)  : 3(tall white)  :  3(short violet)  :  1(short white)
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