Question

A tangent st to a circle touches it at b ab is a chord such that angle abt=65° find angle aob where o is the centre of the circle

Answer 1

Answer:

Explanation:

In the figure,

angle OBT =90 °(OB radius and BT is tangent)

Therefore

angle OBA =90°-65°=25°

Since OA=OB= radius of the circle,

Angle OBA=angleOAB=25°

Therefore, in triangle OBA, AngleOBA + angle OAB+Angle AOB=180°

Angle AOB=180°-(25°+25°)=130°

Answer 2

Answer:

angle aob is 130°

Explanation:

refer ATTACHMENT

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