Question

A tangential force of F = 1.5 N acts on a particle of mass m = 2 kg revolving in a circular path of radius r = 3m. What is the work done by the torque for a complete revolution of the particle?

Answer 1

Answer:

991N

Explanation:

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Answer 2

Answer:

9π

Explaination:

We Know,

τ=r×F

τ=1.5×3=4.5 kgm/s

W=∫ 02π

τ.dθ=4.5(θ f−θ i)=4.5×2π=9π

Hence 9π is the correct answer.