A tank 15m long, 10 m wide and 6 m deep is to be made. It is open at the top. Find the cost of iron sheet, at the rate of Rs. 12.50 per metre, if the sheet is 4 m wide.
Answers
Given :
- Length of the tank = 15m
- Breadth of the tank = 10 m
- Height of the tank = 6 m
- Breadth of the iron sheet = 4 m
- Rate of the iron sheet = Rs. 12.50 per metre.
To find :
- The cost of iron sheet =?
Step-by-step explanation :
Firstly we have to find the Lateral surface area of the tank, because tank is opened at top
Now,
Lateral surface area of tank = 2h( l + b )
Substituting the values in the above formula, we get,
= 2(6)[ 15 + 10 ] m²
= [ 12 × 25 ] m²
= 300 m²
Therefore, The Lateral Surface Area of cylinder = 300 m²
Now,
We have to find the Area of the iron sheet,
So,
Area of the iron sheet = Area of rectangle = length x breadth.
Substituting the values in the above formula, we get,
= [15 x 10] m²
= 150 m²
Therefore, Area of the iron sheet = 150 m²
Now,
Total Area of the tank = Lateral surface area of cylinder + Area of the iron sheet
Substituting the values, we get,
= 300 + 150 m²
= 450 m²
Therefore, Total Area of the tank = 450 m².
Now, Let a sheet cover such area of cuboid.
Length of sheet × breadth of sheet = Area covered
Length × 4 m = 450 m²
Length = 450/4
Length = 112.5 m
Now,
Cost of iron sheet = Length of sheet × Rate of iron sheet per metre
Substituting the values, we get,
= 112.5 × Rs. 12.5
= Rs. 1,406.25
Hence, Cost of iron sheet = Rs. 1,406.25
Answer:
Cost of iron sheet = ₹1406.25
Step-by-step explanation:
Length of tank = 15m
Breadth of tank = 10m
Height of tank = 6m
LSA of tank = 2h ( l + b)
= 2×6 ( 15 + 10)
= 12 × 25
= 300 sq. m
And,
Area of iron sheet = 15 × 10
= 150 sq. m
Now,
Total area of tank = LSA of tank + ar. of iron sheet
= 300 + 150
= 450 sq. m
Total area of tank = 450 sq. m
Area covered = Length of sheet × breadth of sheet
450 = length × 4
=> Length of sheet = 450/4
=> Length of sheet = 112.5 m
Since,
Rate of iron sheet = ₹12.50 /m
Therefore,
Cost of iron sheet = 112.5 × 12.5
= ₹1406.25