a tank can be filled by 2 taps P and Q in 8 hours and 12 hours respectively. The full tank can be emptied by third tap in 8 hours. if all the taps be turned on at the same time, in how much time will the emptied tank be filled up completely ??
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P = 8 hrs
Q = 12 hrs
Tap p can fill 1/8 of the tank in one hour
Tap q can fill 1/12 of the tank in one hour
Tap 3 can empty 1/8 of the tank in one hour
Thus , in one hour(1/8 + 1/12 - 1/8),I.e, 1/12 = 12 hours
Q = 12 hrs
Tap p can fill 1/8 of the tank in one hour
Tap q can fill 1/12 of the tank in one hour
Tap 3 can empty 1/8 of the tank in one hour
Thus , in one hour(1/8 + 1/12 - 1/8),I.e, 1/12 = 12 hours
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Answer:
p= 8 hour
q=12 hour
tap p can fill water in 1 hour =1/8
" q """""""""""""""""""""""""""""""=1/12
so ,
one tap more came (r)
Now,
1/8+1/12-1/8
1/12
12 hours
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