Math, asked by akash472, 1 year ago

(sinX+cosX)(tanX+cotX)=secX+cosecX prove both are equal

Answers

Answered by InnocentBachiNo1
2
↑Above is the required answer.
Note: I used A instead of X.
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Answered by Anonymous
1
Hi friend,

Here is your answer,
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To prove : (sinx+cosx)(tanx+cotx) = secx+cosecx

LHS = (sinx+cosx)( sinx   + cosx )
                               cosx      sinx

        = (sinx+cosx )(sin²x+cos²x)
                               (cosx.sinx)

        = (sinx+cosx)(     1       )
                             (cosx.sinx)

        = (sinx+cosx)
            cosx.sinx
        =         sinx          +          cosx         
             cosx.sinx              cosx.sinx
        = ¹/cosx + ¹/sinx
        = secx + cosecx
        =  RHS

Hence Proved.
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