Question

-A tank can be filled by taps A and B in 10 minutes and 15 minutes respectively. A third tap C can empty this
tank completely in 8 minutes. If all the three taps are turned on at the same time find the time taken to fill the
tank.
एक टंकी जो कि दो नलों A व B से भरती है जो क्रमशः 10 मिनट और 15 मिनट भरने में लेते है। इसी टंकी को तीसरा नल C, 8 मिनट में
खाली करता है। यदि तीनों नलों को एक साथ खोला जाये तो यह टंकी कितने समय में भरेगी?​

Answer 1

Answer:

Let the two side angles be equal to the launch angle θ (see Fig. 1). The maximum height h reached by the projectile is equal to one-half of H, the altitude of this triangle. = H – ½H so h = H/2, which is the desired result.

Answer 2

Step-by-step explanation:

Let total capacity of tank be 1

If tap A , B can fill completely in 10 and 15 minutes respectively then

Amount of tank filled by A in 1 minute = 1/10

Amount of tank filled by B in 1 minute = 1/15

If pipe C can empty tank in 8 minute then

It can empty 1/8 tank / minute

So

Total capacity of tank = ( capacity of tank filled per minute ) × total time taken

1 = (1/10+ 1/15 - 1/8) × time taken

1 = (1/6 - 1/8 ) × time taken

1 = 1/24 × time taken

:. Time taken = 24 minutes

HOPE IT IS HELPFUL