Question

A tank can be filled by two taps a and B in 8 hours and 12 hours respectively the full tank can be emptied by the third pipe in 24 hours if all the three pipes are open at the same time, in how much time will the empty tank be filled

Answer 1

Answer:

..

Step-by-step explanation:

let us assume that total volume of tank is =v

now rate to fill tank of A is=v/8(m^3/h)

and like this

rate of B=v/12

now let assume x hours will taken to fill tank by both.

so here we have

x(v/8+v/12)=v

5xv/24=v

x=24/5h.

x=4h and 48 minutes.