Question

answer this question thanku bro for give me ur id and thanks for help me​

Answer 1

Answer:

don't thank to me

and here ur answer

Answer 2

Answer:

(1/√1 + cot²A)

Step-by-step explanation:

1 + cot²A = cosec²A

=> cosec²A = 1 + cot²A

=> cosecA = ±√1 + cot²A

Here, A is acute. [less than 90]

When A is acute, cosecA is positive.

=> cosecA = √1 + cot²A

We know,

SinA = (1/cosecA)

=> sinA = (1/√1 + cot²A)

Hence, SinA in terms of cotA = (1/√1 + cot²A)

#Hope my answer helped you!