A tank contain two layers of liquids, water (p= 1000 kg /m3) and mercury (p= 13600 kg / m3) . A cube with the edges of length 0.3 m and having the mass of 100 kg is lowered into the tank. Describe the position of cube when it reaches the equilibrium​
Answers
In equilibrium position 0.24 m of its height is in water while 0.6 m of its height is in mercury.
Explanation:
As shown in the figure let us assume that in equilibrium condition x m of the cube lies in water
Length of the cube in Mercury = 0.3-x
From the concept of buoyancy
Weight of the cube = Buoyant Force on the cube due to water + Buoyant force on the cube due to Mercury
m
Therefore, length of the cube in mercury
m
Hence in equilibrium position 0.24 m of its height is in water while 0.6 m of its height is in mercury.
Hope this answer is helpful.
Know More:
Q: Two bodies are in equilibrium in water from the arms of a balance the mass of a body is 36g and density is 9g/cm if the mass of other is 48 kg its density in g/cm is:
Click Here: https://brainly.in/question/1919946
Q: A mixture containing two liquids visibly separated, is placed in a separating funnel. answer the following
1.what type of liquids from the mixture
2.which of the liquids will form the lower layer.
3.what is the principle behind this method of separation
Click Here: https://brainly.in/question/1452278