Question

A tank fills completely in 2 hours if both the taps are open. If only one of the taps is open at the

given time, the smaller tap takes 3 hours more than the larger one to fill the tank. How much

time does each tap take to fill the tank completely?​

Answer 1

Step-by-step explanation:

Assume smaller tap take 'A' hours to fill larger tap " 'B' hours "

(

A

1

+

B

1

)×2=1

A=3+B

3+B

1

+

B

1

=

2

1

3B+B

2

B+3+B

=

2

1

4B+6=3B+B

2

B

2

−B−6=0

B

2

−3B+2B−6=0

B(B−3)2(B−3)=0

(B−3)(B+2)=0

B=3−2soB=3(+ve)

Smaller tap =6hrs.

larger tap =3hrs.

Answer 2

Answer:

Both the taps fill half the tank together in one hour.

Smaller tap will do it in 6 hours, larger one in 3 hours.