A tank fills completely in 2 hours if both the taps are open. If only one of the taps is open at the
given time, the smaller tap takes 3 hours more than the larger one to fill the tank. How much
time does each tap take to fill the tank completely?
Answers
Answered by
1
Step-by-step explanation:
Assume smaller tap take 'A' hours to fill larger tap " 'B' hours "
(
A
1
+
B
1
)×2=1
A=3+B
3+B
1
+
B
1
=
2
1
3B+B
2
B+3+B
=
2
1
4B+6=3B+B
2
B
2
−B−6=0
B
2
−3B+2B−6=0
B(B−3)2(B−3)=0
(B−3)(B+2)=0
B=3−2soB=3(+ve)
Smaller tap =6hrs.
larger tap =3hrs.
Answered by
3
Answer:
Both the taps fill half the tank together in one hour.
Smaller tap will do it in 6 hours, larger one in 3 hours.
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