Question

A tank fills completely in 2 hours if both the taps are open. Ifonly one of the taps is open at the given time, the smaller tap
takes 3 hours more than the larger one to fill the tank. How muchtime does each tap take to fill the tank completely?




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Answer 1

1 hour

2x-1x =x

x/x=1

so, answer is 1 hour

Answer 2

Given

A tank fills completely in 2 hours if both the taps are open. Ifonly one of the taps is open at the given time, the smaller tap

takes 3 hours more than the larger one to fill the tank. How muchtime does each tap take to fill the tank completely?

Answer;

Let larger tap can fills the tank in = x hrs.

then smaller tap will fill the tank in = (x+3) hrs

Part of the tank filled in an hr by both taps =1/x+1/(x+3) acordingly:-

1/x + 1/(x+3) = 1/2

(x+3+x)/x.(x+3) =1/2

or (2x+3)/(x^2+3x) = 1/2

or x^2+3x = 4x+6

or x^2 - x - 6 = 0

or (x-3) (x+2) = 0

x= 3 , -2(Negligenle )

Larger tap can fills the tank in = x hrs = 3 hrs.

Smaller tap can fills in = (x+3 )=(3+3)= 6 hrs

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