A tank has two inlet pipes A nd B which can fill the tank in 12h and 18 h respectively and an outlet C can empty the tank in 9h.A,B and C are opened at a time ,but the outlet C blocked completely after 6 h.Find the total time taken right from the start to fill the tank.
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Answer:
Cistern filled by both pipes in one hour = 1/12+1/20=2/15th
Therefore both pipes filled the cistern in 15/2hrs.
Now, due to leakage both pipes filled the cistern in 15/2+30/60=8hrs.
Therefore Due to leakage, filled part in one hour = 1/8
Therefore part of cistern emptied, due to leakage in one hour = 2/15-1/8= 1/120th
In 120 hrs, the leak would empty the cistern
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