Question

a tank in a shape of frustum having diameter of top and bottom are 6m and 10 m respectively if the height is 3 m then how many litres of oil can be filled in it how many drums of 200 litres each can be filled​

Answer 1

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Answer 2

Capacity of the tank is 154000 liters and 770 drums of 200 liters each can be filled with oil

Step-by-step explanation:

Volume of frustum = $\pi \frac{h}{3}[r_1^2+r_2^2+r_1\times r_2]$

here,

π = $\frac{22}{7}$

h = 3 meter

r₁ = Radius = $\frac{diameter}{2}$ = 6/2 = 3 meter

r₂ = 10/2 = 5 meter

Volume or capacity of frustum = $\frac{22}{7}\times \frac{3}{3}[3^2+5^2+3\times 5]$ meter³

                                                  = 3.14[9+25+15]

                                                  = 3.14 × 49

                                                  = 153.86 meter³ ≈ 154 m³

1 meter³ = 1000 liter

154 meter³ = 154000 liters

Capacity of each drum to be filled = 200 liters

number of drums can be filled = $\frac{154000}{200}$

                                                   = 770

Capacity of the tank is 154000 liters and 770 drums of 200 liters each can be filled with oil.

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