A tank initially at rest is filled with water up to a height h a small orifice is made at the bottom of the wall find the velocity attained by the tank will it becomes completely empty assume that the mass of the tank and the friction to be negligible
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A tank initially at rest is filled with water up to a height h
Kinetic energy at Rest = 0
Potential Energy = mgh
m = mass of water
Total energy = mgh
when water will be empty
Potential energy = 0 as m = 0 no water
Kinetic energy = (1/2)mv² ( v = velocity of Tank)
Total energy = (1/2)mv²
as no frictional loss so
(1/2)mv² = mgh
=> v² = 2gh
=> v =√2gh
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