(A tank is filled by three pincesh uniform flow. The first two pipes operating simultaneously fill the
fank in the same time during which the tank is filled by the third pipe alone. The second pipe fill the
tank 5 hours faster than the first pipe and 4 hours slower than the third pipe. Find the time required by
the first pipe.
Answers
Step-by-step explanation:
Answer:
Solution:
Let the number of Rs.50 notes be A and the number of Rs.100 notes be B
According to the given information,
A + B = 25 ……………………………………………………………………….. (i)
50A + 100B = 2000 ………………………………………………………………(ii)
When equation (i) is multiplied with (ii) we get,
50A + 50B = 1250 …………………………………………………………………..(iii)
Subtracting the equation (iii) from the equation (ii) we get,
50B = 750
B = 15
Substituting in the equation (i) we get,
A = 10
Hence, Manna has 10 notes of Rs.50 and 15 notes of Rs.100.Answer:
Solution:
Let the fixed charge be Rs x and per km charge be Rs y.
According to the question,
x + 10y = 105 …………….. (1)
x + 15y = 155 …………….. (2)
From (1), we get x = 105 – 10y ………………. (3)
Substituting the value of x in (2), we get
105 – 10y + 15y = 155
5y = 50
y = 10 …………….. (4)
Putting the value of y in (3), we get
x = 105 – 10 × 10 = 5
Hence, fixed charge is Rs 5 and per km charge = Rs 10
Charge for 25 km = x + 25y = 5 + 250 = Rs 255
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Answer:
Solution :-
↦Let, the first number be x
↦ Second number be x + 1
↦ Third number be x + 2
↦ Fourth number be x + 3
↦ Fifth number be x + 4
↦ And, the addition of five consecutive numbers is 270.
According to the question,
⇒ x + x + 1 + x + 2 + x + 3 + x + 4 = 270
⇒ x + x + x + x + x + 1 + 2 + 3 + 4 = 270
⇒ 5x + 10 = 270
⇒ 5x = 270 - 10
⇒ 5x = 260
⇒ < /p > < p > x = < /p > < p > \dfrac{260}{5} \: ⇒</p><p>x=</p><p>
5
260
➠x=52
Hence, the required numbers are,
✦ First number = x = 52
✦ Second number = x + 1 = 52 + 1 = 53
✦ Third number = x + 2 = 52 + 2 = 54
✦ Fourth number = x + 3 = 52 + 3 = 55
✦ Fifth number = x + 4 = 52 + 4 = 56
But, in question we have to find the addition of second and fifth number,
➳ Second number + Fifth number
➳ 53 + 56
\implies < /p > < p > 109 \: ⟹</p><p>109
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hopethishelpsu
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Hope this helps u