a tank is filled by two pipes P and Q. If P takes 2 hrs more than Q to fill the tank alone and P and Q together fill the tank in 1 by 7 upon 8 hrs, then find the time taken by P and Q alone to fill the tank.
Answers
Answered by
0
If P takes x hours
Q takes x -2 hours
Rate of P = 1/x per hour
Rate of Q = 1/(x-2) per hour
Working together = 1/x + 1/(x-2) per hour
= (2x-1)/x(x-1)
Total time taken by the two taps = x(x-1)/(2x-1) = 1(7/8)
This simplifies to:
4x2 – 23x + 15 = 0
Solving this quadratic equation gives
x = ¾
OR
x = 5
We take x = 5
x – 2 = 3
P takes 5 hours
Q takes 3 hours
Attachments:
Similar questions