A tank is fitted with two taps.the first tap can fill the tank completely in 45 minutes and the second tap can empty the full tank in one hour. if both the taps are opened alternately for one minute, then in how many hours the empty tank will be filled completely ?
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The total time taken to fill the tank is 5 hours and 53 minutes.
Step-by-step explanation:
We are given that
- In first minute tap A fills 4 units of water
- In second minute B empty 3 units of water
- After two minutes tanks has 1 units of water.
Total capacity = 180 units
Now by decrease 4 from the total capacity = 180 − 4 = 176 units.
1 unit filled in 2 minutes
176 units filled in = 176 x 2 = 352 minutes
Now in next minutes pipe A will fill 4 units and tank is full.
Total time taken is 352 + 1 = 353 minutes
OR 5 hour and 53 minutes
Thus the total time taken to fill the tank is 5 hours and 53 minutes.
Also learn more
Find the time required to fill a cylindrical water tank of radius 2 m and height 7 M through a pipe at the rate of 11 per minute ?
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